8/(t^2)=2

Solution for 8/(t^2)=2 equation:

8/(t^2)=2

We move all terms to the left:

8/(t^2)-(2)=0


Domain of the equation: t^2!=0

t^2!=0/

t^2!=√0

t!=0

t∈R


We multiply all the terms by the denominator


-2*t^2+8=0

We add all the numbers together, and all the variables

-2t^2+8=0

a = -2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-2)·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-2}=\frac{-8}{-4}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-2}=\frac{8}{-4}
=-2
$